This technical problem deals with singly linked lists, and specifically with checking if a given singly linked list is a palindrome. A palindrome is defined as a word, phrase , or sequence that reads the same backward as forward, and so in this context, a palindrome linked list would be one where the order of the nodes is the same whether you traverse the list from the beginning or from the end. The input to the function is a singly linked list, and the output is a boolean value indicating whether or not the list is a palindrome.
About this solution: The candidate's solution correctly implements a function to check if a singly linked list is a palindrome. The candidate uses a stack to store the data from the first half of the list, then compares the data in the second half of the list to the data in the stack. If the data doesn't match, the list is not a palindrome.
The candidate's solution is complete and correctly solves the problem. The candidate's approach is sound.
This problem asks you to reverse a singly linked list. An example input is given as 1->2->3->4->5, and the expected output is 5->4->3 ->2->1.
About this solution: The candidate's solution correctly implements a solution to reverse a singly linked list, both iteratively and recursively. The iterative solution is more efficient, however, both solutions are correct. The candidate demonstrates a good understanding of linked lists and how to reverse them.
Given a singly linked list, this function returns the middle node of the list. If the list has an even number of nodes, the function returns the node at the start of the second half of the list.
About this solution: The candidate's solution is complete and solves the problem. The candidate's approach is to create a linked list from the given vector data, print the list, and then find the middle node of the list.