Partitioning
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This technical problem deals with writing a SQL query to find the most recent date for each unique value in a table. The table given in the example has two columns, one for dates and one for unique values. The expected output is also given in the example.
About this solution: The solution above is optimal because it uses a subquery to find the most recent date for each unique value. This is the most efficient way to solve the problem and will work for any size table.
Given a list of customer names and corresponding orders, this SQL query will find the customer who has placed the most orders.
About this solution: The candidate's solution correctly finds the customer with the most orders.
The query is well-organized and easy to follow.
The use of GROUP BY, ORDER BY, and LIMIT is efficient and concise.
Overall, the candidate demonstrates a good understanding of SQL and how to solve this problem.