Problem

Given a list of integers, return the sum of the integers at the odd indices.
Input: [1, 2, 3, 4, 5]
Output: 9

Solution

// Solution:

function sumOddIndices(arr) {
  let sum = 0;
  for (let i = 0; i < arr.length; i++) {
    if (i % 2 !== 0) {
      sum += arr[i];
    }
  }
  return sum;
}

// Explanation:
// This solution is optimal because it uses a for loop to iterate through the array and add the values at the odd indices to a sum variable.
// The for loop is optimal because it is the most efficient way to iterate through an array.
// The if statement is optimal because it is the most efficient way to check if the index is odd.
// The sum variable is optimal because it is the most efficient way to store the sum of the values at the odd indices.
// The return statement is optimal because it is the most efficient way to return the sum variable.