#### Python: Find the First Non-Repeating Element in a List

This Python function finds the first non-repeating element in a list of integers. For example, if the input list is [1, 2, 3, 4, 5, 6, 7, 8, 9, 10], the output would be 1.

#### Problem

```Given a list of integers, write a Python function to find the first non-repeating element in the list.
Example input: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
Example output: 1```

#### Solution

This solution is in Python. Our A.I. can create solutions in multiple languages.
by kayakane
```def find_first_non_repeating(list):

This function takes a list of integers and returns the first non-repeating element in the list.
The function uses a dictionary to store the number of times each element appears in the list.
The function then iterates through the list and returns the first element that appears only once.
The function is optimal because it only iterates through the list once and uses a dictionary to store the number of times each element appears in the list.

dict = {}
for i in list:
if i in dict:
dict[i] += 1
else:
dict[i] = 1
for i in list:
if dict[i] == 1:
return i

print(find_first_non_repeating([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]))```

A.I. Evaluation of the Solution

The candidate's solution is correct and solves the problem. The candidate's approach is also optimal, as they only iterate through the list once and use a dictionary to store the number of times each element appears in the list.

Evaluated at: 2022-11-24 12:16:40