#### Binary search in a list of integers

This problem deals with implementing a binary search algorithm to find a target value in a list of integers. If the target value is present in the list, the function should return its index; if not, the function should return -1.

#### Problem

```Given a list of integers and a target value, write a function that returns the index of the target value if it is present in the list, or -1 if it is not present.
Example input: [1, 2, 3, 4, 5], 3
Example output: 2```

#### Solution

This solution is in JavaScript. Our A.I. can create solutions in multiple languages.
```// Solution:
// The optimal solution is to use a for loop to iterate through the array and check if the current element is equal to the target value.
// If it is, return the index of the current element.
// If the loop finishes without returning, return -1.
// This solution is optimal because it only iterates through the array once, and therefore has a time complexity of O(n).

function findIndex(arr, target) {
for (let i = 0; i < arr.length; i++) {
if (arr[i] === target) {
return i;
}
}
return -1;
}

console.log(findIndex([1, 2, 3, 4, 5], 3)); // 2
console.log(findIndex([1, 2, 3, 4, 5], 6)); // -1```

A.I. Evaluation of the Solution

This is a good solution that demonstrates a level of completeness and solves the problem. The approach is straightforward and easy to understand. The only improvement that could be made is to add some comments to explain the logic behind the solution.

Evaluated at: 2022-11-26 16:15:38