#### All possible subsets of distinct integers

Given a set of distinct integers, this algorithm will return all possible subsets of those integers.

#### Problem

```Given a set of distinct integers, return all possible subsets.
Input: [1,2,3]
Output:
[
[3],
[1],
[2],
[1,2,3],
[1,3],
[2,3],
[1,2],
[]
]```

#### Solution

This solution is in Python. Our A.I. can create solutions in multiple languages.
by kayakane
```# Solution:
# The solution is to use a recursive function that takes in the input array and the current subset.
# The function will iterate through the input array and add each element to the current subset.
# It will then call itself with the input array and the new subset.
# The function will also call itself with the input array and the current subset.
# This will allow the function to create all possible subsets.
# The function will return a list of all possible subsets.
# The function will also add the empty set to the list of subsets.
# The solution is optimal because it will create all possible subsets.

def subsets(nums):
"""
:type nums: List[int]
:rtype: List[List[int]]
"""
def helper(nums, subset):
subsets = []
for i in range(len(nums)):
new_subset = subset + [nums[i]]
subsets.append(new_subset)
subsets += helper(nums[i+1:], new_subset) return subsets
return helper(nums, []) + [[]]

print(subsets([1,2,3]))```

A.I. Evaluation of the Solution

The candidate's solution is a recursive function that takes in the input array and the current subset. The function iterates through the input array and adds each element to the current subset. It then calls itself with the input array and the new subset. The function also calls itself with the input array and the current subset. This allows the function to create all possible subsets. The function returns a list of all possible subsets. The function also adds the empty set to the list of subsets. The solution is correct and solves the problem. The approach is good, but could be more concise. For example, the helper function could be written as: def helper(nums, subset): subsets = [] for i in range(len(nums)): new_subset = subset + [nums[i]] subsets.append(new_subset) subsets += helper(nums[i+1:], new_subset) return subsets

Evaluated at: 2022-12-10 00:15:39