#### Determine if a singly linked list is a palindrome.

This problem asks whether a singly linked list is a palindrome, meaning that the data in the list is the same forwards as it is backwards. An example input is provided, along with the expected output.

#### Problem

```Given a singly linked list, determine if it is a palindrome.
Example input:
1->2->2->1
Example output:
true```

#### Solution

This solution is in C++. Our A.I. can create solutions in multiple languages.
by kayakane
```#include <iostream>
#include <string>
#include <vector>
#include <algorithm>
#include <sstream>
#include <queue>
#include <deque>
#include <bitset>
#include <iterator>
#include <list>
#include <stack>
#include <map>
#include <set>
#include <functional>
#include <numeric>
#include <utility>
#include <limits>
#include <time.h>
#include <math.h>
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <assert.h>

using namespace std;

struct Node {
int data;
Node* next;
};

Node* newNode(int data) {
Node* node = new Node;
node->data = data;
node->next = NULL;
return node;
}

cout << head->data << " ";
}
cout << endl;
}

stack<int> s;
while (fast != NULL && fast->next != NULL) {
s.push(slow->data);
slow = slow->next;
fast = fast->next->next;
}
if (fast != NULL) {
slow = slow->next;
}
while (slow != NULL) {
int top = s.top();
s.pop();
if (top != slow->data) {
return false;
}
slow = slow->next;
}
return true;
}

int main() {