#### Reversing a singly linked list.

This problem asks you to reverse the order of the nodes in a singly linked list. For example, if the input list is 1->2->3->4->5, the output should be 5->4->3->2->1.

#### Problem

```Given a singly linked list, reverse the order of the nodes in the list.
Example input:
1->2->3->4->5
Example output:
5->4->3->2->1```

#### Solution

This solution is in Python. Our A.I. can create solutions in multiple languages.
by kayakane
```class Node:
def __init__(self, data):
self.data = data
self.next = None

def __init__(self):

def push(self, new_data):
new_node = Node(new_data)

def printList(self):
while(temp):
print(temp.data)
temp = temp.next

def reverse(self):
prev = None
while(current is not None):
next = current.next
current.next = prev
prev = current
current = next

llist.push(5)
llist.push(4)
llist.push(3)
llist.push(2)
llist.push(1)

llist.print List()
llist.reverse()
llist.printList()```

A.I. Evaluation of the Solution

The candidate's solution correctly reverses the order of the nodes in a singly linked list. The approach is straightforward and easy to follow.

Evaluated at: 2022-11-11 04:15:54